The angular frequency of a physical pendulum is
$\begin{align*}\omega = \sqrt{\frac{M g d}{I}}\end{align*}$
where $I$ is the moment of inertia about the pivot point and $d$ is the distance from the pivot to the center of mass.
If we let $l$ denote the length of the pendulum and $m$ denote the mass of the identical masses, then
$\begin{align*}I_I &= 2 m l^2 \\I_{II} &= \frac{5 m l^2}{4} \\d_I &= l \\d_{II} &= \frac{3 l}{4}\end{align*}$
Therefore,
$\begin{align*}\frac{f_{II}}{f_I}= \frac{\omega_{II}}{\omega_I} = \frac{\sqrt{\displaystyle \frac{M g d_{II}}{I_{II}}}}{\sqrt{...$
Therefore, answer (A) is correct.

Solution to 1992 Problem 61